Question

Помогите решить пожалуйста

Answer 1

$Sin \alpha =- \sqrt{1-Cos ^{2} \alpha }=- \sqrt{1-(-0,8) ^{2} } =- \sqrt{1-0,64}=- \sqrt{0,36}=$$-0,6\\\\tg \alpha = \frac{Sin \alpha }{Cos \alpha }= \frac{-0,6}{-0,8}= \frac{3}{4}\\\\Ctg \alpha = \frac{1}{tg \alpha } = \frac{1}{ \frac{3}{4} }= \frac{4}{3}=1 \frac{1}{3}$


$Sin \alpha =- \sqrt{1-Cos ^{2} \alpha }=- \sqrt{1-( \frac{24}{25}) ^{2} }=- \sqrt{1- \frac{576}{625} } =- \sqrt{ \frac{49}{625} }=- \frac{7}{25} \\\\tg \alpha = \frac{Sin \alpha }{Cos \alpha }= \frac{ \frac{-7}{25} }{ \frac{24}{25} } =- \frac{7}{24} \\\\Ctg \alpha = \frac{1}{tg \alpha } = \frac{1}{- \frac{7}{24} } =- \frac{24}{7}=-3 \frac{3}{7}$