Question

sin($\frac{5}{6}$+a), если sina= корень 3/2 и 0<a<п/2

Answer 1

sina=√3/2
cosa=√(1-sin²a)=√(1-3/4)=√(1/4)=1/2
sin(π/6+a)=sinπ/6cosa+cosπ/6sina=1/2*1/2+√3/2*√3/2=1/4+3/4=1