Question

(X-4)(x+3)+(x+3)(x-2)=0
Найти x

Answer 1

(X-4)(x+3)+(x+3)(x-2)=0

x²+3x-4x-12+x²-2x+3x-6=0

2x²-18=0
x²=9
x1=3
x2=-3

Answer 2

(X-4)(x+3)+(x+3)(x-2)=0
x²+3x-4x-12+x²-2x+3x-6=0
2x²-12-6=0
2x²=12+6
2x²=18
x²=9
x=3