Question

121x3-22x2+x=0 решите уравнение

Answer 1

х(121х²-22х+1)=0
х=0
121х²-22х+1=0
$x1.2 = \frac{ 22 + - \sqrt{ {22}^{2} - 4 \times 121 } }{2 \times 121} = \frac{22}{242} = \frac{1}{11}$