Question

найти область определения функции

Answer 1

4-9/(x+1)+1/(x-3)≥0
(4x²-8x-12-9x+27+x+1)/(x+1)(x-3)≥0
(4x²-16x+16)/(x+1)9x-3)≥0
4(x²-4x+4)/(x+1)(x-3)≥0
4(x-2)²/(x+1)(x-3)≥0
x=2  x=-1  x=3
    +              _               _             +
--------(-1)----------[2]----------(3)---------
x∈(-∞;-1) U (3;∞) U{2}