Question

22.4 liters of HCL dissolved in 200 milliliters of H2O calculate the volume part of HCL

Answer 1

n(HCl)=22.4/22.4=1mol'
m(HCl)=1mol'*36.5g mol'=36.5g
p(H20)=1g m3
m(H20)=200ml*1g m3=200g
w(HCl)=36,5/200=0,1825*100=18.25%