Question

1)1+x^2=-2x
2)-x^2=9-6x

Answer 1

$1+ x^{2} =-2x \ x^{2} -2x+1=0 \ a=1; b=-2; c=1 \ D= b^{2}-4ac=4-4=0 \ x= frac{-b}{2a}= frac{2}{2}=1$
Ответ: $x=1$
$- x^{2} =9-6x \ - x^{2} +6x-9=0 \ a=-1; b=6; c=-9 \ D= b^{2} -4ac=36-4*9=36-36=0 \ x= frac{-b}{2a}= frac{-6}{-2} =3$
Ответ: $x=3$