Question

2cos(2x-п/6)=v2 v-Корень.
Пожалуйста)

Answer 1

сos(2x-π/6)=√2/2
2x-π/6=-π/4+2πk U 2x-π/6=π/4+2πk
2x=-π/12+2πk U 2x=5π/12+2πk
x=-π/24+πk U x=5π/24+πk,k∈z