Question

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Answer 1

2) 2cos²(π/3)+sin²(π/6)=2*(1/2)²+(1/2)²=2*1/4+1/4=3/4

б) (0.3+sin²30°-cos²30°)/(2*sin(-30°))=
=(0.3-cos60°)/(-2*sin30°)=(0.3-1/2)/(-2*1/2)=(3/10-5/10)/(-1)=2/10=1/5