Question

-2t^2+8t+2=0
Решение

Answer 1

-2t²+8t+2=0
a=-2 b=8 c=2
D=b²-4ac=64+4*2*2=64+16=80
t1=-b+✓D/2a=-8+√80=-8+4√5
t2=-b-✓D/2a=-8-✓80=-8-4√5
Ответ: t1=-8+4✓5
t2=-8-4✓5

Answer 2

2t²-8t-2=0
D=64+16=80
t1=8+√80/4 = 8+4√5/4 = 2+√5
t2=2-√5