Question

найдите производную:
f(x)= ctgx^3-7x
f(x)=-6x^2×cosx^3
f(x)=-9tg(10x)

Answer 1

3) dy/dx=f'(x)
$frac{dy}{dx} = - 9times frac{1}{ {cos}^{2}10x } times 10 = \ =-frac{90}{ {cos}^{2}10x }$
1)
$frac{dy}{dx} = - frac{1}{ {sin}^{2} {x}^{3} } times 3 {x}^{2} - 7 = \ = - frac{3 {x}^{2} }{ {sin}^{2} {x}^{3} }-7$
2)
$frac{dy}{dx} = - 6(2x times cos {x}^{3} + \ + {x}^{2} times ( - sin {x}^{3} ) times 3 {x}^{2} ) = \ = - 6x(2cos {x}^{3} - 3 {x}^{3} sin {x}^{3} )$