Question

Найдите значение выражения arcsin(-1/2)+arccos(-√2/2)-arctg√3

Answer 1

arcsin(-1/2)+arccos(-√2/2)-arctg√3=-π/6+3π/4-π/3=(-2π+9π-4π)/12=
=3π/12=π/4

Answer 2

https://znanija.com/task/27864552