Question

9≥|12-(х+3)|>-1
Решите, пожалуйста, системой неравенств! СРОЧНО!!! ОЧЕНЬ НУЖНО!!!!!

Answer 1

$9 geq |12-(x+3)| geq- 1\-1 leq |12-x-3| leq 9\-1 leq |9-x| leq 9\-1 leq |x-9| leq 9\\ left { {{|x-9| geq -1} atop {|x-9| leq 9}} right. = textgreater left { {{xin R} atop {-9 leq x-9 leq 9}} right. = textgreater left { {xin R} atop {-9+9leq x leq 9+9}} right. = textgreater left { {{x in R} atop {0 leq x leq 18}} right.\\xin[0;18]$