Question

Даю 49
б Решите уравнение.
x^2+3x+9/x^3+27 - 1/x+3 = 2/x^3-3x+9

Answer 1

(x²+3x+9)/(x+3)(x²-3x+9)-1/(x+3)=2/(x²-3x+9)
x³++27≠0⇒x³≠-27⇒x≠-3
(x²+3x+9)-(x²-3x+9)-2(x+3)=0
x²+3x+9-x²+3x-9-2x-6=0
4x=6
x=1,5