Question

срочно помогите с первым вариантом даю 20баллов

Answer 1

1)
a)
$4+12x textgreater 7+13x \-x textgreater 3 \x textless -3 \ xin(-infty;-3)$

b)
$-(2-3x)+4(6+x) textgreater 1 \ -2+3x+24+4x textgreater 1 \7x textgreater -21 \ x textgreater -3 \xin(-3;+infty)$

2)
$left { {{3x+4 leq 4x+6} atop {x-5 leq 4-2x}} right. \\ left { {{-x leq2} atop {3xleq9}} right. \\ left { {{x geq -2} atop {xleq3}} right. \\ xin[-2;3]$

3)
$-3 textless 2-5x textless 1 \ -3-2 textless -5x textless 1-2 \-5 textless -5x textless -1 \1 textless 5x textless 5 \ 0.2 textless x textless 1 \ xin(0.2;1)$