Question

x^3 - 4x^2 - 9x +36 = 0

Answer 1

$x^3-4x^2-9x+36=0\x^2(x-4)-9(x-4)=0\(x-4)(x^2-9)=0\x-4=0\x=4\x^2-9=0\x=3\x=-3$