Question

помогите 1 и 2 решить

Answer 1

2x² + x - 3x³ = x(2x + 1 - 3x²) = - x(3x² - 2x - 1) = - 3x(x - 1)(x + 1/3) = x(1 - x)(3x + 1)

y³ - 2y² + y = y(y² - 2y + 1) = y(y - 1)² = y(y - 1)(y - 1)