Question

Докажите тождество (1,2x^4-7y^2)(1,2x^4+7^2)+0,56x^8+49y^4=2x^8

Answer 1

(1,2x⁴ - 7y²)(1,2x⁴ + 7y²) + 0,56x⁸ + 49y⁴ = 2x⁸
(1,2x⁴)² - (7y²)² + 0,56x⁸ + 49y⁴ = 2x⁸
1,44x⁸ - 49y⁴ + 0,56x⁸ + 49y⁴ = 2x⁸
(- 49y⁴ и 49y⁴ сокращаем)
1,44x⁸ + 0,56x⁸ = 2x⁸
2x⁸ = 2x⁸