Question

Решите систему уравнений

Answer 1

x=$frac{352}{y}$
($frac{352}{y}$ -2 ) (y+4)=400

$frac{14088}{y}$ -2y+344=400

Answer 2

-2y^2 +344y-400y+1408=0 -> y=16;-44-> x=22;-8

Answer 3

$x = frac{352}{y} \ (frac{352}{y} - 2)(y + 4) = 400 \ frac{(352 - 2y)(y + 4)}{y} = 400 \ 352y + 1408 - 2 {y}^{2} - 8y - 400y = 0 \ - 2 {y}^{2} - 56y + 1408 = 0 \ {y}^{2} + 28y - 704 = 0 \ d = 784 - 4 times ( - 704) = 3600 \ y_{1} = frac{ - 28 - 60}{2} = - 44 \ y_{2} = frac{ - 28 + 60}{2} =16 \ x_{1} = frac{352}{ - 44} = - 8 \ x_{2} = frac{352}{ 16} =22$

Ответ: (-8; -44), (22; 16)