Question

how many grams nitric acid can be obtained from 2 mol ammoniac

Answer 1

Have:
n(NH₃) - 2 mol
To find: m(HNO₃)
Solve:
The ratio of ammonia to nitric acid is 1:1
NH₃ → HNO₃
$n = frac{m}{M}$
n(HNO₃) = 2 mol
m(HNO₃) = n(HNO₃) · M(HNO₃) = 2 · (1+14+16·3) = 2 · 63 = 126 g/mol
Answer: m(HNO₃) = 126 g/mol

Answer 2

thank you)

Answer 3

np

Answer 4

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