Question

Упростите:

$frac{1+cosx}{sinx} - frac{sinx}{1-cosx}$

Answer 1

$frac{1+cosx}{sinx} - frac{sinx}{1-cosx} = frac{(1+cosx)(1-cosx) - sin(x)^2}{sinx(1-cosx)} = frac{1-cos(x)^2 - sin(x)^2}{sinx(1-cosx)} =$
$frac{sin(x)^2 - sin(x)^2}{sinx(1-cosx)} = frac{0}{sinx(1-cosx)} = 0$