Question

Выполнить действия с комплексными числами:

Answer 1

1
x1=5-3i,x2=5+3i
p=-(x1=x2)=-(5-3i+5+3i)=-10
q=x1*x2=(5-3i)(5+3i)=25-9i²=25+9=34
x²-10x+34=0
2
(5-3i)(5-3i)/(5+3i)(5-3i)=(25-30i-9)/34=(16-30i)/34=8/17-15/17*i
3
(3+5i)(-2+i)=-6+3i-10i+5i²=-6-7i-5=-11-7i