Question

#1091 пж мне срочно

Answer 1

∠COD = ∠DOB+∠BOC
∠DOB = ∠COD-∠BOC = 48°-34° = 14°

∠AOB = ∠AOD+∠DOB
∠AOD = ∠AOB-∠DOB = 100°-14° = 86°

Answer 2

спасибо!!