Question

(n+1)!×(n+3)!/(n+4)! сократите дробь. решите плиз

Answer 1

(n+1!)*(n+3!)/(n+4!)=(n+1)*(n+1*2*3)/(n+1*2*3*4)=(n+1)*1/n*4=(n+1)*n/4n=n+1/4