Question

8*√2*cos(-π/3)*sin(-π/4)-tg(π/4)+ctg(-π/2)

Answer 1

$8 times sqrt{2} cos(-pi/3) times sin(-pi/4)-tg(pi/4)+ctg(-pi/2) = \ = 8 sqrt{2} times frac{1}{2} times ( - frac{ sqrt{2} }{2} ) - 1 + 0 = \ = - frac{8 sqrt{2} sqrt{2} }{4} - 1 = - 4 - 1 = - 5$