Ответы
Ответ дал:
0
5
cosacosb-sinasinb=cos(a+b)
cosπ/5cos2π/15-sinπ/5sin2π/15=cos(π/5+2π/15)=cos(3π/15+2π/15)=сos5π/15=
=сosπ/3=1/2
6
sinacosb-sinbcosa=sin(a-b)
sin5π/24cos3π/8-cos5π/24sin3π/8=sin(5π/24-3π/8)=sin(-π/6)=-1/2
cosacosb-sinasinb=cos(a+b)
cosπ/5cos2π/15-sinπ/5sin2π/15=cos(π/5+2π/15)=cos(3π/15+2π/15)=сos5π/15=
=сosπ/3=1/2
6
sinacosb-sinbcosa=sin(a-b)
sin5π/24cos3π/8-cos5π/24sin3π/8=sin(5π/24-3π/8)=sin(-π/6)=-1/2
Ответ дал:
0
cos(π/5+2π/15)=cos 5π/15
Вас заинтересует
2 года назад
2 года назад
3 года назад
3 года назад
9 лет назад
10 лет назад