Question

Решите уравнения:
1) x+8 целых 1/11=16,1
2) y-9,7=8 целых 2/3

Answer 1

1.
$x + 8 frac{1}{11} = 16.1$
$x + frac{8}{11} = 16.1$
$x = 16.1 - frac{8}{11}$
$x = frac{161}{10 } - frac{8}{11}$
$x = frac{1691}{110}$

2.
$y - 9.7 = 8 frac{2}{3}$
$y - 9.7 = frac{16}{3}$
$y = frac{16}{3} + 9.7$
$y = frac{16}{3} + frac{97}{10}$
$y = frac{451}{30}$

Answer 2

1)х+8 1/11=16,1
х=16 1/10-8 1/11
х= 8 1/110

2)у-9,7=8 2/3
у=8 2/3+9 7/10
у=18 11/30