Question

1) x/(x-1)+3x/(x^2-3x+2)=6/(x-2)
2) (x+1)/(x+)+10x/(x^2+x-6) помогите плизз

Answer 1

$1). \ frac{x}{x-1} + frac{3x}{ x^{2} -3x+2} = frac{6}{x-2} \ x^{2} -3x+2=0 \ a=1;b=-3;c=2 \ D= b^{2} -4ac=9-4*2=9-8=1 \ x_{1} = frac{-b+ sqrt{D} }{2a} = frac{3+1}{2} = frac{4}{2} =2 \ x_{2} = frac{-b- sqrt{D} }{2a} = frac{3-1}{2} = frac{2}{2} =1 \ frac{x}{x-1} + frac{3x}{(x-2)(x-1)} = frac{6}{x-2} \ frac{x(x-2)}{(x-2)(x-1)} + frac{3x}{(x-2)(x-1)} - frac{6(x-1)}{(x-2)(x-1)} =0 \ frac{x(x-2)+3x-6(x-1)}{(x-2)(x-1)} =0 \ frac{ x^{2} -2x+3x-6x+6}{(x-2)(x-1)} =0$$frac{ x^{2} -5x+6}{(x-2)(x-1)} =0 \ x^{2} -5x+6=0 \ a=1;b=-5;c=6 \ D= b^{2} -4ac=25-4*6=25-24=1 \ x_{1} = frac{-b+ sqrt{D} }{2a} = frac{5+1}{2} = frac{6}{2} =3 \ x_{2} = frac{-b- sqrt{D} }{2a} = frac{5-1}{2} = frac{4}{2} =2 \ frac{(x-3)(x-2)}{(x-2)(x-1)} =0 \ frac{(x-3)}{(x-1)} =0$

Answer 2

??

Answer 3

хз

Answer 4

где условие?

Answer 5

(x+1)/(x+3)+10x/(x^2+x-6)=4.(x-2)

Answer 6

это?