Question

Решите уравнения:а) (-2,5-х)(0,8+х)=0 и б) (56,78+у)(24-у)(-у-24)=0

Answer 1

(-2,5 - x )(0,8 + x ) = 0
(-5/2 - x )(4/5 + x ) = 0
-5/2 - x = 0
4/5 + х = 0
x₁ = -5/2
x₂ = -4/5

(56,78 + y)(24 -y)(-y - 24) = 0
(2839/50 + y)(24-y)(-y-24) = 0
2839/50 + y = 0
24 - y = 0
-y - 24 = 0
y₁ = - 2839/50
y₂ = -24
y₃ = 24