Question

решите неравенство 2х^2+3х+37<(х+7)^2

Answer 1

2х^2+3х+37<(х+7)^2
2x^2+3x+37<x^2+14x+49
x^2-11x-12<0
D=121+4*12=169=13^2
x1=(11+13)/2=12
x2=(11-13)/2=-1
x∈(-1;12)