Question

помогите пожалуйста 49 и 50

Answer 1

49)
$S = frac{1}{2} * BC * AM = frac{BC^2*sqrt{3}}{4} |*frac{4}{BC}\ 2AM = BCsqrt{3} \ 12 sqrt{3} = BCsqrt{3} | : sqrt{3} \ BC = 12 \ P = 3BC = 36 (cm)$

50)
$S = frac{1}{2} * AC * BK = frac{AC^2*sqrt{3}}{4} |*frac{4}{AC}\ 2BK = ACsqrt{3} \ 4 sqrt{3} = ACsqrt{3} | : sqrt{3} \ AC = 4 \ S = frac{1}{2} * AC * BK = frac{1}{2} * 4* 2sqrt{3} = 4sqrt{3} (cm^2)$