Question

В край нужно срочняк плеззз

Answer 1

№2.
$frac{b^2}{2b-a} *(2- frac{a}{b} ) = frac{b^2}{2b-a} * frac{2b -a}{b} = frac{(b*b) *(2b-a)}{b(2b-a)}= frac{b*1*1}{1*1}= frac{b}{1} =b \ \ frac{d^3}{c-3d} * ( frac{c}{d} -3) = frac{d^3}{c-3d} * frac{c-3d}{d} = frac{d^2}{1} =d^2$

$frac{5+3x}{x^5 } : ( frac{3}{5} + frac{1}{x} ) = frac{5+3x}{x^5 } : frac{3x + 1*5}{5x} = frac{5+3x}{x^5 } : frac{5+3x}{5x} = frac{5+3x}{x^5} * frac{5x}{5+3x} = frac{5}{x^4} \ \ frac{3+2y}{y^4} : ( frac{2}{3} + frac{1}{y} )= frac{3+2y}{y^4} : frac{2y +1*3}{3y} = frac{3+2y}{y^4} * frac{3y}{3+2y} = frac{3}{y^3}$

Answer 2

спс бро