Question

Решите неравенство:а) |10х+1|>21;б) |2-6х|<4

Answer 1

Решите неравенство

а) |10х+1|>21

$left[begin{array}{ccc} 10x+1 textgreater 21\ 10x+1 textless -21end{array}right \ \ \ left[begin{array}{ccc} 10x textgreater 20\ 10x textless -22end{array}right \ \ \ left[begin{array}{ccc} x textgreater 2\ x textless -2,2end{array}right$

Ответ: 
$x textless -2,2 ; x textgreater 2$


б) |2-6х|<4

$left { {{2-6x textless 4} atop { 2-6x textgreater -4 }} right. \ \ left { {{6x textgreater -2} atop { 6x textless 6 }} right. \ \ left { {{x textgreater - frac{1}{3} } atop { x textless 1 }} right.$

Ответ: 
$- frac{1}{3} textless x textless 1$

Answer 2

Спс бро