Question

3y^2+4y=4
Подробно с ответами и формулами.пишите на листке

Answer 1

3y^2 + 4y = 4 
3y^2 + 4y - 4 = 0
D = 4^2 - 4*3*(- 4 ) = 16 + 48 = 64 = 8^2 
y1 = ( - 4 + 8 ) : ( 2 * 3 ) = 4 : 6 = 2/3 
y2 = ( - 4 - 8 ) : ( 2 * 3 ) = - 12 : 6 = - 2 

Answer 2

3y² + 4y = 4
3y² + 4y - 4 = 0
a = 3, b = 4, c = -4
D = b² - 4ac = 4² - 4 * 3 * (-4) = 16 + 48 = 64
√D = √64 = 8
x1 = (-b + √D)/2a = (-4 + 8)/6 = 4/6 = 2/3
x2 = (-b - √D)/2a = (-4 - 8)/6 = -12/6 = -2