Question

$\frac{10 {x}^{3} - 15x {y}^{2} }{21x {y}^{3} - 14 {y}^{4} }$

Answer 1

$\frac{10 x^{3} -15x y^{2} }{21xy^{3}-14y^{4} } = \frac{5x(2 x^{2} -3y^{2}) }{7 y^{3} (3x-2y)}$