Question

Помогите прошу пожалуйста

Answer 1

$\frac{cos(59+360)-3sin(90+59)}{3sin(90-59)-5sin(149+360)}= \\ \\ \frac{cos(59)-3cos(59)}{3cos(59)-5sin(149)}= \frac{-2cos(59)}{3cos(59)-5sin(90+59)}= \frac{-2cos(59)}{3cos(59)-5cos(59)}= \\ \\ \frac{-2cos(59)}{-2cos(59)} =1$