Question

А1❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Answer 1

$(\sqrt[3]{7\sqrt7}-\sqrt[5]{25\sqrt5}):(\sqrt{7}+\sqrt5)+\sqrt{35}=\\\\=(\sqrt[3]{7^{3/2}}-\sqrt[5]{5^{5/2}}):(\sqrt7+\sqrt5)+\sqrt{35}=\\\\=\frac{(\sqrt7-\sqrt5)(\sqrt7-\sqrt5)}{(\sqrt7+\sqrt5)(\sqrt7-\sqrt5)}+\sqrt{35}= \frac{7-2\sqrt{5\cdot 7}+5}{7-5}+\sqrt{35} =\\\\= \frac{12-2\sqrt{35}}{2}+\sqrt{35}=6-\sqrt{35}+\sqrt{35}=6\\\\\\60\%\; ot\; x=0,6x\; \; =\; 6\; \; \Rightarrow \; \; x= \frac{6}{0,6}=10$

Число равно 10 .