Question

5x·(12x+7)-4x·(15x-11)=10+29x

Answer 1

$5x(12x+7)-4x(15x-11)=10+29x$
$60x^2+35x-60x^2+44x=10+29x$
$50x=10$
$x= \frac{1}{5} =0,2$

Answer 2

5x(12x+7)-4x(15x-11)=10+29x
60x²+35x-60x²+44x=10+29x
60x²+35x-60x²+44x-29x=10
50x=10
x=10/50=1/5=0,2
5*0,2(12*0,2+7)-4*0,2(15*0,2-11)=10+29*0,2
Ответ:x=0,2