Question

Разложите на множители.(3y+4x)^2
(10-4c)^2
(-2y+5c)^2

Answer 1

(3y+4x)^2=(3y+4x)(3y+4x)
(10-4c)^2=(10-4c)(10-4c)=2(5-2c)*2(5-2c)=4(5-2c)(5-2c)
(-2y+5c)^2=(-2y+5c)(-2y+5c)