Question

пж 1 вариант 1-ое задание,2 и 3

Answer 1

1) а)12(b-x)+b(b-x)=(12+b)(b-x)
б)7y²(3y+1)-15(3y+1)=(7y²-15)(3y+1)

2)5c(x-c)+x(x-c)=(5c+x)(x-c)
(5*1+(-2))(-2-1)=3*(-3)=-9

3) 4.1(6.4+3.6)+2.2(3.6+6.4)=10(4.1+2.2)=10*6.3=63