Question

решите уравнение (5х-1)(х+2)+3(х-4)(х+4)=2(2х+3)²-8

Answer 1

(5х-1)(х+2)+3(х-4)(х+4)=2(2х+3)²-8
5х²-х+10х-2+3(х²-4х+4х-16)=2(4х²+6х+9)-8
5х²-х+10х-2+3(х²-16)=8х²+12х+18-8
5х²-х+10х-2+3х²-48=8х²+12х+18-8
5х²-х+10х+3х²-8х²-12х=18-8+2+48
-3х=60
х=-20

Answer 2

Ответ:

{–4}

Пошаговое объяснение:

(5х–1)(х+2)+3(х–4)(х+4)=2(2х+3)²–8

5х²–х+10х–2+3(х²–16)=2(4х²+12х+9)–8

5х²–х+10х–2+3х²–48=8х²+24х+18–8

8х²+9х–50=8х²+24х+10

8х²+9х–8х²–24х=10+50

–15х=60

х= 60:(–15) = –4