Question

Решите пожалуйста очень надо

Answer 1

1)2/x-3-1/x=6/x²-3x x≠3, x≠0
2/x-3-1/x-6/x(x-3)=0
2x-(x-3)-6/x(x-3)=0
2x-x+3-6/x(x-3)=0
x-3/x(x-3)=0
1/x=0 x принадлежит ∅
2)3у-3/3у-2+6+2у/3у+2=2 y≠2/3 y≠-2/3
9y²-9y+6y-6+18y+6y²-12-4y-18y²+8/(3y-2)(3y+2)=-3y²+11y-10/(3y-2)(3y+2)=3y²-11y+10=0
D=121-4*3*10=1 y1=11+1/6=2 y2=11-1/6=5/3
3)8c-3/4c²-2c+1+6/8c³+1=2/2c+1 c≠-1/2
(2c+1)(8c-3)+6-2(4c²-2c+1)/(2c+1)(4c²-2c+1)=0
16c²-6c+8c-3+6-8c²+4c-2/(2c+1)(4c²-2c+1)=0
8c²+4c+2c+1/(2c+1)(4c²-2c+1)=0
4c(2c+1)+2c+1/(2c+1)(4c²-2c+1)=0
(2c+1)(4c+1)/(2c+1)(4c²-2c+1)=0
4c+1/4c²-2c+1=0
4c=-1
c=-1/4