Question

Помогите пожалуйста!!!!!!!!!!!!!!!!!!!
Даю 30 баллов

Answer 1

а) 
$\frac{3x+1}{x+1} + \frac{3+x}{x+1} = \frac{3x+1+3+x}{x+1} = \frac{4x+4}{x+1} = \frac{4(x+1)}{x+1} =4$
б)
$\frac{3x}{x-4} + \frac{x+8}{4-x} = -\frac{3x}{4 -x} + \frac{x+8}{4-x} = \frac{-3x+x+8}{4-x} = \\ \\ =\frac{8-2x}{4-x} = \frac{2(4-x)}{4-x} =2$
в)
$\frac{5x+1}{x-1} - \frac{6}{x-1} = \frac{5x+1-6}{x-1} = \frac{5x-5}{x-1} = \frac{5(x-1)}{x-1} =5$
г)
$\frac{5x-3}{x-3y} - \frac{1-5y}{3y-x} = \frac{5x-3}{x-3y} + \frac{1-5y}{x-3y} = \\ \\ = \frac{5x-3+1-5y}{x-3y} = \frac{5x-5y-2}{x-3y} = \\ \\ =\frac{(x-3y)+4x-2y-2 }{x-3y} =1+2* \frac{2x-y-1}{x-3y}$