Question

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1) 3x²- х = 24

2)4x²=-4-1

3)-25=10х+ x²

Answer 1

1) 3х^2-х=24
3х^2-х-24=0
D=(-1) ^2-4×3×(-24) =1+288=289
x=1+-17 /6
х1=3, х2= -2 2/3

3) -25=10+х^2
-х^2-10х-25=0
D=(-10) ^2-4×(-1) ×(-25) =100-100=0
x= -10/2=-5

Answer 2

$3 {x}^{2} - x = 24 \ 3 {x}^{2} - x - 24 = 0 \ a = 3 : : : b = - 1 : : : c = - 24 \ d = {b}^{2} - 4ac = {( - 1)}^{2} - 4 times 3 times ( - 24) = 1 + 240 + 48 = 289 = {17}^{2} \ x1 = frac{1 + 17}{2 times 3} = frac{18}{6} = 3 \ x2 = frac{1 - 17}{6} = frac{ - 16}{6} = - frac{8}{3}$



$- 4 {x}^{2} = - 4 - 1 \ - 4 {x}^{2} + 4 + 1 = 0 \ - 4 {x}^{2} + 5 = 0 \ a = - 4 : : : : b = 0 : : : : c = 5 \ d = {0}^{2} - 4 times ( - 4) times 5 = 80 ={( 4 sqrt{5} )}^{2} \ x1 = frac{0 + 4 sqrt{5} }{ - 8} = - frac{ sqrt{5} }{2} \ x2 = frac{ sqrt{5} }{2}$

$- 25 = 10x + {x}^{2} \ {x}^{2} + 10x + 25 = 0 \ d = 100 - 4 times 1 times 25 = 0 \ x1 = x2 = frac{ - 10 + 0}{2} = - 5$