Question

Решите уравнение
log_3 x+ log_3=2

Answer 1

Решение
Log3 X +logx 3 =2
x > 0, x ≠ 1
log₃ x + log₃ 3/log₃ x = 2
log₃ ² - 2log₃x + 1 = 0
log₃x = z
z² - 2z + 1 = 0
(z - 1)² = 0
z = 1
log₃x = 1
x = 3