Question

-1/2 < sinx < sqrt(3)/2

Answer 1

-1/2 < sinx < √(3)/2
Рассмотрите два неравенства
1) -1/2 < sinx
-π/6 +2πn <х< 7π/6 +2πn, nєZ
2) sinx < √(3)/2
2π/3 +2πn
xє(-π/6 +2πn;π/3 +2πn)U(2π/3 +2πn;7π/6 +2πn), nєZ