Question

x2-12=0 x1=12 x2=0 Это правельно ?

Answer 1

${x}^{2} - 12 = 0 \ {x}^{2} = 12 \ x = + - sqrt{12} \ x1 = sqrt{12} = 2 sqrt{3} \ x2 = - sqrt{12} = - 2 sqrt{3}$