Question

$64 {a}^{3} - frac{1}{27} {b}^{3 }$

Answer 1

$64a^3-frac{1}{27}b^3=(4a-frac{1}{3}b)(16a^2+1frac{1}{3}ab+frac{1}{9}b^2)$

Answer 2

$64 {a}^{3} - frac{1}{27} {b}^{3} = (4a - frac{1}{3} b)(16 {a}^{2} + frac{4}{3} ab + frac{1}{9} {b}^{2} )$