Question

Разложите на множители
b^6-4b^4+12b^2-9

Answer 1

b⁶-4b⁴+12b²-9=(b³)²-(2b²-3)²=(b³+2b²-3)(b³-2b+3)=
(b³-b²+3b²-3b+3b-3)(b³+b²-3b²-3b+3b+3)=
(b²(b-1)+3b(b-1)+3(b-1))(b²(b+1)-3b(b+1)+3(b+1))=
(b-1)(b²+3b+3)(b+1)(b²-3b+3)

Answer 2

спасибо