Question

4-sin^2x=0
4sin3x*cos3x=2

Answer 1

4 - sin²x = 0

sin²x = 4 - не имеет решений, т.к. -1 ≤ sinx ≤ 1

2) 4sin3xcos3x = 2
2sin6x = 2
sin6x = 1

6x = πk

x = πk/6, k∈Z